Rohit Sharma’s 70, Trent Boult’s 4-fer steer them to 7-wicket victory over SRH
Hyderabad: A rampant Mumbai Indians rode on Rohit Sharma’s (70) second consecutive fifty to pulverise a hapless Sunrisers Hyderabad by seven wickets in their Indian Premier League match here on Wednesday.
Mumbai Indians’ fourth win on the trot, which took them to the third spot from the earlier sixth on the points table, came after SRH posted a below-par 143/8 and Rohit making the most of the perfect batting conditions to score 70 off 46 balls (8x4s, 3x6s).
MI scored 146/3 in 15.4 overs to win the match with 26 balls to spare, with Suryakumar Yadav hitting a 19-ball 40 not out (5x4s, 2x6s).
The fate of the contest was all but sealed when SRH crumbled to 35/5 following an embarrassing collapse. Despite Heinrich Klaasen’s 71 and Abhinav Manohar’s 43, the hosts did not have enough runs on the board to challenge MI’s batting might.
The five-time winners recorded their third consecutive win while chasing, having drubbed Chennai Super Kings by nine wickets last Sunday.
It was also their second win over SRH in the season, having beaten them by four wickets last week in Mumbai.
Earlier, Klaasen’s measured 71 and Manohar’s 43 rescued a listless SRH from a terrible start and guided them to 143/8.
Klaasen struck nine fours and two sixes for his 44-ball 71, putting on 99 runs for the sixth wicket with impact substitute Abhinav Manohar, who played a steady second fiddle with his 37-ball 43 (2x4s, 3x6s).
But it was a harrowing start for SRH who are placed second-last on the points table and face an uphill battle to keep themselves alive.
